A positive integer is called an Armstrong number of order n if
abcd... = an + bn + cn + dn + ...
In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example:
153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number.
Check Armstrong Number of n digits
#include < stdio.h >
#include < math.h >
int main()
{
int number, originalNumber, remainder, result = 0, n = 0 ;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
originalNumber /= 10;
++n;
}
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += pow(remainder, n);
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
Output
Enter an integer: 1634
1634 is an Armstrong number.
abcd... = an + bn + cn + dn + ...
In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example:
153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number.
Check Armstrong Number of n digits
#include < stdio.h >
#include < math.h >
int main()
{
int number, originalNumber, remainder, result = 0, n = 0 ;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
originalNumber /= 10;
++n;
}
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += pow(remainder, n);
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
Output
Enter an integer: 1634
1634 is an Armstrong number.
No comments