A wall clock gains 2 minutes in 12 hours, while a table clock loses 2 minutes in 36 hours; both are set right at noon on Tuesday. The correct time when they both show the same time next would be
(1) 12:30 night
(2) 12 noon
(3) 1:30 night
(4)
12 night
Answer: 1
Solution: The wall clock gains 6 minutes in 36 hours, while the table clock loses 2 minutes in 36 hours. Hence, time differential in 36 hours = 8 minutes. For them to show the same time again, we need a total time differential of 0 mins. It occurs at 12:30 night.
Alternate Method:
In 36 hours Clock1 gains 6mins while clock2 loses 2 mins. (ratio 3:1)
For the condition to be satisfied, the time gained by clock1 and that lost by clock2 should add upto 12 hours(720 mins)
From these 2 conditions we have to divide 720 mins in the ratio 3:1
ie ( 540 : 180 )
ie, Clock 1 has gained 540 mins and clock 2 has lost 180 mins when they show the correct time again.
That will be after 36 * 90 = 3240 hours = 3240/24 = 135 days exactly.
So, they will both show the correct time at 12 noon
Correct Answer: 1
Solution:
The wall clock gains 6 minutes in 36 hours, while the table clock loses 2 minutes in 36 hours. Hence, time differential in 36 hours = 8 minutes. For them to show the same time again, we need a total time differential of 0 mins. It occurs at 12:30 night.
Alternate Method:
In 36 hours Clock1 gains 6mins while clock2 loses 2 mins. (ratio 3:1)
For the condition to be satisfied, the time gained by clock1 and that lost by clock2 should add upto 12 hours(720 mins)
From these 2 conditions we have to divide 720 mins in the ratio 3:1
ie ( 540 : 180 )
ie, Clock 1 has gained 540 mins and clock 2 has lost 180 mins when they show the correct time again.
That will be after 36 * 90 = 3240 hours = 3240/24 = 135 days exactly.
So, they will both show the correct time at 12 noon
(1) 12:30 night
(2) 12 noon
(3) 1:30 night
(4)
12 night
Answer: 1
Solution: The wall clock gains 6 minutes in 36 hours, while the table clock loses 2 minutes in 36 hours. Hence, time differential in 36 hours = 8 minutes. For them to show the same time again, we need a total time differential of 0 mins. It occurs at 12:30 night.
Alternate Method:
In 36 hours Clock1 gains 6mins while clock2 loses 2 mins. (ratio 3:1)
For the condition to be satisfied, the time gained by clock1 and that lost by clock2 should add upto 12 hours(720 mins)
From these 2 conditions we have to divide 720 mins in the ratio 3:1
ie ( 540 : 180 )
ie, Clock 1 has gained 540 mins and clock 2 has lost 180 mins when they show the correct time again.
That will be after 36 * 90 = 3240 hours = 3240/24 = 135 days exactly.
So, they will both show the correct time at 12 noon
Correct Answer: 1
Solution:
The wall clock gains 6 minutes in 36 hours, while the table clock loses 2 minutes in 36 hours. Hence, time differential in 36 hours = 8 minutes. For them to show the same time again, we need a total time differential of 0 mins. It occurs at 12:30 night.
Alternate Method:
In 36 hours Clock1 gains 6mins while clock2 loses 2 mins. (ratio 3:1)
For the condition to be satisfied, the time gained by clock1 and that lost by clock2 should add upto 12 hours(720 mins)
From these 2 conditions we have to divide 720 mins in the ratio 3:1
ie ( 540 : 180 )
ie, Clock 1 has gained 540 mins and clock 2 has lost 180 mins when they show the correct time again.
That will be after 36 * 90 = 3240 hours = 3240/24 = 135 days exactly.
So, they will both show the correct time at 12 noon
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